3*n^2+11*n-2484=0

Solution for 3*n^2+11*n-2484=0 equation:

3n^2+11n-2484=0

a = 3; b = 11; c = -2484;
Δ = b2-4ac
Δ = 112-4·3·(-2484)
Δ = 29929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{29929}=173$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-173}{2*3}=\frac{-184}{6}
=-30+2/3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+173}{2*3}=\frac{162}{6}
=27
$